Posted by **Anonymous** on Monday, December 13, 2010 at 9:57pm.

A person fishing hooks a 3.0-kg fish on a line that can only sustain a maximum of 35 N of force before breaking. At one point while reeling in the bass, it fights back with a force of 45 N. What is the minimum acceleration with which you must play out the line during this time in order to keep the line from breaking?

- physics -
**drwls**, Tuesday, December 14, 2010 at 12:18am
If the fish does actually exert a force of 45 N on the line, it will break. It exerts its force mainly on the water around it, away from the fisherman. If it accelerates backwards in the process due to released line, a line at its breaking point exerts a force on the fish (and vice versa) equal to 45 N - Ma = 35 N. The backwards acceleration of the fish is then

a = 10 N/g = 1.02 m/s^2

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