Posted by **dazed and confused** on Monday, December 13, 2010 at 9:36pm.

dy/dx[tan(y)=x=y] in terms of y

the answer my teacher got was cot^2(y) but i get is 1/[sec^2(y)-1]

either i made a mistake, my teacher made a mistake or we're both right and i just need to simplify.

please tell me which of the following is the case and how to get to the correct answer.

- Calculus -
**Reiny**, Monday, December 13, 2010 at 10:32pm
let's see if cot^2 y = 1/(sec^2 y - 1 )

RS = 1/(1/cos^2y - 1)

= 1/((1 - cos^2y)/cos^2y)

= 1/((sin^2y/cos^2))

= cos^2y/sin^2y

= cot^2 y

so you are both right!

- Calculus -
**dazed and confused**, Monday, December 13, 2010 at 10:41pm
ok, thank you. is it preferable to change it like that? cause i honestly have no idea why it would matter.

- Calculus -
**dazed and confused**, Monday, December 13, 2010 at 10:44pm
oh and just to be clear you got this using trig identities right?

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