Posted by **Leonardo Figueroa** on Monday, December 13, 2010 at 9:07pm.

You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?

- physics -
**Omer**, Monday, December 13, 2010 at 9:30pm
Remember the equation: deltaF = ma

In this case delta F is the force applied(800N)-Force of friction.

Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.

u is given(.2)

N(the normal force)opposes the downward force of the desk(mg)250*9.81.

Thus Ff=.2*250*9.81=490.5

Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.

800-490.5=250a

309.5/250=a

1.24=a

theres your answer, hope i helped

- 11th grade -
**drwls**, Tuesday, December 14, 2010 at 12:55am
Omer is correct. Thanks for helping, Omer

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