Monday

March 2, 2015

March 2, 2015

Posted by **Leonardo Figueroa** on Monday, December 13, 2010 at 9:07pm.

- physics -
**Omer**, Monday, December 13, 2010 at 9:30pmRemember the equation: deltaF = ma

In this case delta F is the force applied(800N)-Force of friction.

Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.

u is given(.2)

N(the normal force)opposes the downward force of the desk(mg)250*9.81.

Thus Ff=.2*250*9.81=490.5

Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.

800-490.5=250a

309.5/250=a

1.24=a

theres your answer, hope i helped

- 11th grade -
**drwls**, Tuesday, December 14, 2010 at 12:55amOmer is correct. Thanks for helping, Omer

**Answer this Question**

**Related Questions**

physics - Imagine yourself seated on a wheeled desk chair at your desk. Consider...

PHYSICS - Example 2: a) A desk has a mass of 68.75 kilograms. If the coefficient...

Physics - In moving a 35.0 kg desk from one side of a classroom to the other, a ...

Physics - In moving a 35.0 kg desk from one side of a classroom to the other, a ...

Physics - a student pushes on a desk with a force of 75 N causing it to begin ...

Biomechanics - If John was pushing a 300 kg desk across the floor with a ...

physics - A desk weighing 80 N rests on the floor. The coefficient of friction ...

physics - A 6.110 kg block of wood rests on a steel desk. The coefficient of ...

Physics - A 4.500 kg block of wood rests on a steel desk. The coefficient of ...

physics - A 4.170 kg block of wood rests on a steel desk. The coefficient of ...