Posted by Leonardo Figueroa on Monday, December 13, 2010 at 9:07pm.
You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?

physics  Omer, Monday, December 13, 2010 at 9:30pm
Remember the equation: deltaF = ma
In this case delta F is the force applied(800N)Force of friction.
Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5
Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.
800490.5=250a
309.5/250=a
1.24=a
theres your answer, hope i helped

11th grade  drwls, Tuesday, December 14, 2010 at 12:55am
Omer is correct. Thanks for helping, Omer
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