Posted by **Anna** on Monday, December 13, 2010 at 7:49pm.

How do I start to solve -2log8(x+1) = -8?

I think -2log8(x+1) is log8^(x+1)to the 2nd but then what do I do because then I think I should do log-8/log8 = x+1)^2 but that doesn't work at all

Thank you for any help you can give

- Algebra-Could Mathmate or Reiny or Dr. Bob look at this if you have time -
**Anna**, Monday, December 13, 2010 at 8:52pm
Please give me some direction for the above problem

Thank you

- Algebra -
**Reiny**, Monday, December 13, 2010 at 9:45pm
-2log8(x+1) = -8

first of all, multiply be -2

log8(x+1) = 4

log_{8}(x+1)^2 = 8

(x+1) = 8^4

x = 4095

## Answer This Question

## Related Questions

- Algebra-Reiny please explain this - Hi Reiny, I posted this problem earlier and ...
- College Algebra - 1. 2log8^x=log8(4x+12) both log bases are 8. I have no clue ...
- Algebra 1 - solve: log8(w-6)=2-log8(w+15) note: the 8 is to be little at the ...
- Test prep - solve: log8(w-6)=2-log8(w+15) note: the 8 is to be little at the ...
- Algebra 2 - Solve the equation : 8^2x-1 = 16^x+1 i know you have to log both ...
- College Algebra - I REALLY don't understand the reason/basis/use of logarithms. ...
- Math - Log8 4 + log16 2 x log 27 81= x solve for x
- calc - Find the missing value: 1) log _____ = 1/2 Solve the equation, round to ...
- Log Algebra - Find the inverse of the function y=log8 x
- college - Write as a single log : 3log2+2log8- 1/2 log4 ( simplify your answer...

More Related Questions