Let x be an integer. What is the product of twice the integer added to three times the next consecutive integer?
6x^2+6x
just kidding Nate has the right answer
Math mate has right equation
I have no Freaking clue
To find the product of twice the integer added to three times the next consecutive integer, we first need to understand what it means for x to be an integer and how to find the next consecutive integer.
1. Let's start with the definition of an integer. An integer is a whole number, either positive, negative, or zero, without any decimal or fractional parts. For example, -3, 0, and 7 are all integers.
2. Now, let's find the next consecutive integer. To do this, we simply add 1 to the given integer. So, if x is the given integer, the next consecutive integer is x + 1.
3. Next, we want to calculate twice the given integer. To do this, we multiply the given integer by 2. So, twice the integer is 2x.
4. Similarly, we want to calculate three times the next consecutive integer. We multiply the next consecutive integer (x + 1) by 3. So, three times the next consecutive integer is 3 * (x + 1).
5. Finally, we need to find the product of twice the integer added to three times the next consecutive integer. We simply multiply the two expressions we calculated in the previous steps. So, the product is (2x) * (3 * (x + 1)).
In summary, the product of twice the integer added to three times the next consecutive integer is (2x) * (3 * (x + 1)).
x=integer
What is the product of twice the integer (=2x) added to three times the next consecutive integer (3*(x+1))
Multiply together and simplify:
2x(3*(x+1))
=6x(x+1)