Lisa drops a stone from a wall that is 7.00m from the ground. How long is the stone in the air?
Use:
Distance, S=ut+(1/2)at²
u=initial velocity=0
a=-g
t=time
Solve for t.
Thanks!
To determine how long the stone is in the air, we need to calculate the time it takes for the stone to fall from the wall to the ground. We can use the formula for the time it takes for an object to fall freely:
t = √(2h/g),
where t is the time, h is the height, and g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).
In this case, the height (h) is 7.00 m. Plugging this value into the formula, we get:
t = √(2 * 7.00 m / 9.8 m/s^2).
t = √(14 / 9.8).
t = √1.4286.
t ≈ 1.19 seconds.
Therefore, the stone is in the air for approximately 1.19 seconds before it hits the ground.