Posted by kaitlyn on Monday, December 13, 2010 at 5:44pm.
pressureEachLeg= weight/area * 1/2
so would it be...
P=((73+7)*9.8)/2*pi*r then divide it by 2?
or would it be...
4P=((73+7)*9.8)/2*pi*r then divide it by 2?
No. Area of a circle is PI r^2
so the denominator is / PI r^2 *1/2
which changes all to
pressure= 2*80*g/PI(.01)^2
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