Posted by **kaitlyn** on Monday, December 13, 2010 at 5:44pm.

A 73 kg man in a 7.0 kg chair tilts back so that all the weight is balanced on two legs of the chair. Assume that each leg makes contact with the floor over a circular area with a radius of 1.0 cm, and find the pressure exerted on the floor by each leg.

- physics -
**bobpursley**, Monday, December 13, 2010 at 5:46pm
pressureEachLeg= weight/area * 1/2

- physics -
**kaitlyn**, Monday, December 13, 2010 at 5:52pm
so would it be...

P=((73+7)*9.8)/2*pi*r then divide it by 2?

or would it be...

4P=((73+7)*9.8)/2*pi*r then divide it by 2?

- physics -
**bob pursley**, Monday, December 13, 2010 at 6:07pm
No. Area of a circle is PI r^2

so the denominator is / PI r^2 *1/2

which changes all to

pressure= 2*80*g/PI(.01)^2

## Answer this Question

## Related Questions

- physics - A 73 kg man in a 4.3 kg chair tilts back so that all his weight is ...
- Physics - A 67.8 kg man sits in a 6.3 kg chair so that his weight is evenly ...
- physics - A 70 kg person sits on a 3.6 kg chair. Each leg of the chair makes ...
- Physics please help!! - A 73.5 kg person sits on a 3.20 kg chair. Each leg of ...
- Physics - A chair of weight 85.0N lies atop a horizontal floor; the floor is not...
- physics - A chair of weight 150 lies atop a horizontal floor; the floor is not ...
- physics - A chair of weight 150 lies atop a horizontal floor; the floor is not ...
- Physics - A chair of weight 85.0 N lies atop a horizontal floor; the floor is ...
- physics - A chair of weight 150 lies atop a horizontal floor; the floor is not ...
- physics - A chair of weight 150 lies atop a horizontal floor; the floor is not ...

More Related Questions