Posted by **kaitlyn** on Monday, December 13, 2010 at 5:44pm.

A 73 kg man in a 7.0 kg chair tilts back so that all the weight is balanced on two legs of the chair. Assume that each leg makes contact with the floor over a circular area with a radius of 1.0 cm, and find the pressure exerted on the floor by each leg.

- physics -
**bobpursley**, Monday, December 13, 2010 at 5:46pm
pressureEachLeg= weight/area * 1/2

- physics -
**kaitlyn**, Monday, December 13, 2010 at 5:52pm
so would it be...

P=((73+7)*9.8)/2*pi*r then divide it by 2?

or would it be...

4P=((73+7)*9.8)/2*pi*r then divide it by 2?

- physics -
**bob pursley**, Monday, December 13, 2010 at 6:07pm
No. Area of a circle is PI r^2

so the denominator is / PI r^2 *1/2

which changes all to

pressure= 2*80*g/PI(.01)^2

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