Posted by Gabriela on Monday, December 13, 2010 at 4:31pm.
let the point be P(x,y)
Perimeter = 2x + 2y
= 2x + 2(x^-2)
= 2x + 2/x^2
d(perimeter)/dx = 2 -4/x^3
= 0 for min of perimeter
2 - 4/x^3 = 0
2 = 4/x^3
x^3 = 2
x = 2^(1/3) , (the cube root of 2)
y = 2^(-2/3)
(I really expected the point to be (1,1) but the Calculus shows my intuition was wrong
the perimeter with the above answers is 3.78
had it been (1,1) the perimeter would have been 4)
Try this way:
Perimeter = 2x+2
therefore P = 2x + 2/x^2
d(perimeter)/dx = (2x^3-4)/x^3
solving for x = 2^(1/3)
therefor y was given as y = x^-2
plug x into y to solve for y.
y = 2^(-2/3) or y = (1/4)^(1/3)
check the answer it should be 3.78
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