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How many grams of FeSo4 are required to prepare 0.50 L of a 0.010 M FeSO4 solution?

I don't need the answer just shown how to do it! thanks

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    Look at the units!
    so, given: 0.010 mol/L and 0.50 L
    take the product of (0.010 mol/L)(0.50 L) to get mol of FeSO4. To get grams, multiply by the molar mass of FeSO4

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