Posted by Ivy on Sunday, December 12, 2010 at 8:44pm.
How many moles are present? 1 mole will occupy 22.4 L and it will contain 6.022E23 molecules.
PV=nRT
1 atm *1.00L= n * 0.0821(atm-L/ mol-K) * 273 k
n= 0.0446 mol
0.0446 mol * 6.02 * 10^23 (molecules/mol)=
6.28* 10^22
PV=nRT
1 atm *1.00L= n * 0.0821(atm-L/ mol-K) * 273 k
n= 0.0446 mol
0.0446 mol * 6.02 * 10^23 (molecules/mol)=
6.28* 10^22
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