Find A1 in a geometric series for which Sn=210, r=-2, and n=6?
Can someone lead me in the right direction?
its -10 buddy
u dont know the naswe buddy
listen here buddy the anser is 10?3 oknokkkkook
listen all of u buddies!!!!! the answer to the question lies within ur heart ok so stop fighting love
Sure! To find A1 in a geometric series, we can use the formula for the sum of a geometric series (Sn):
Sn = A1(1 - r^n) / (1 - r)
In this case, we are given Sn = 210, r = -2, and n = 6. Plugging these values into the formula, we get:
210 = A1(1 - (-2)^6) / (1 - (-2))
Simplifying the equation, we have:
210 = A1(1 - 64) / (1 + 2)
210 = A1(-63) / 3
Multiplying both sides by 3, we have:
630 = -63A1
Dividing both sides by -63, we get:
A1 = 630 / -63
A1 = -10
Therefore, A1 in the geometric series is -10.
Sn=A1(1-2^6)/1-2
you should get 10/3