Posted by Tiana on Sunday, December 12, 2010 at 5:53pm.
Let u = x^2 and solve
2u^2 -3u -20 = 0
That can be factored, to give
(2u +5)(u-4) = 0
u = 4 OR -5/2
x = sqrt4 or sqrt(-3/2)
The only REAL zeros are +2 and -2
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