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March 29, 2017

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The diameter of a car's tire is 52 cm. While the car is being driven, the tire picks up a nail. How high above the ground will the nail be after the car has travelled 0.1 km?

can someone please explain how to solve this question?

  • Grade 11 math - HELP! - ,

    C = 3.14 * 52 cm = 163.4 cm/rev.

    0.1 km = 100 m = 10000 cm.

    10000 cm / 163.4 cm/rev - 61.2 REVs.

    d = 0.2 rev * 163.4 cm/rev = 32.7 cm
    above ground.

  • Grade 11 math - HELP! - ,

    Thank youu !

  • Grade 11 math - HELP! - ,

    yolo

  • Grade 11 math - HELP! - ,

    How did you get 0.2 rev?

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