Posted by **Brianna** on Sunday, December 12, 2010 at 2:19pm.

can someone please answer these questions for me?:

1. if the measure of an interior angle of a regular pentagonis 108 degrees, then the angle sum of that regular pentagon must be:

A. 120 degrees

B. 360 degrees

C. 540 degrees

D. 720 degrees

2. is it possible for a parallelogram to have a 38 degree angle and a 145 degree angle? explain please

3. a rectangle has a perimeter of 24 centimeters. one of its sides is 8 centimeters long. what are the dimensions of the rectangle? explain please

4. is it possible for a triangle to have angles with measures of 40 degrees, 115 degrees and 30 degrees? please explain

thanks :D sorry if theres soo many questions, i just really need help

- math -
**Reiny**, Sunday, December 12, 2010 at 2:54pm
sum of interior angles = 180(n-2) where n is the number of sides

so each angle is 180(n-2)/n

180(n-2)/n = 108

180n - 360 = 108n

72n = 360

n = 5

So you have a pentagon

angle sum = 180(5-2) = 540

do the others the same way.

Remember in #2, that n has to be a whole number.

(e.g. A pentagon cannot have 4.3 sides)

#3. Just think about it again.

you have one of the sides.

How does one find the perimeter?

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