Posted by Renee on Sunday, December 12, 2010 at 1:10pm.
well, you need the initial vertical velocity approaching the ditch.
over the ditch, one drops 2.96m. How long does it take to fall that distance?
2.96=1/2 g t^2 or t= sqrt(2*2.96/9.8)=.9455 sec check that.
so, to get across the ditch in this time, velocity= 10m/.9455=10.575m/s
centripetal acceleration= v^2/r
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