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While travelling a distance of 27m the velocity of a train increased from 12m/sec to 54km/hr what is the uniform acceleration of the train.

  • physics -

    54 km/hr = 15 m/s

    Vfinal^2 - Vinitial^2 = 2 a X
    81 m^2/s^2 = 2*a*27m
    Solve for acceleration, a.

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