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Posted by on Sunday, December 12, 2010 at 12:40am.

While travelling a distance of 27m the velocity of a train increased from 12m/sec to 54km/hr what is the uniform acceleration of the train.

  • physics - , Sunday, December 12, 2010 at 1:03am

    54 km/hr = 15 m/s

    Vfinal^2 - Vinitial^2 = 2 a X
    81 m^2/s^2 = 2*a*27m
    Solve for acceleration, a.

  • physics - , Saturday, April 16, 2011 at 6:29am

    1,5

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