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March 28, 2017

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A 4.0 kg pulley of radius 0.15 m is pivoted about an axis through its center. What constant torque is required for the pulley to reach an angular speed of 25 rad/s after rotating 6.0 revolutions, starting from rest?

  • physics - ,

    Torque=momentinertia*anglular acceleration

    Torque= I * angacc


    but

    wf^2=wi^2+2*angacc*displacement

    wf^2=wi^2+2*angacc*revolutions*2PI

    where w is in rad/sec, angacc in rad/sec^2

    solve for angacc, then torque

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