Posted by **erik** on Saturday, December 11, 2010 at 8:01pm.

A 4.0 kg pulley of radius 0.15 m is pivoted about an axis through its center. What constant torque is required for the pulley to reach an angular speed of 25 rad/s after rotating 6.0 revolutions, starting from rest?

- physics -
**bobpursley**, Saturday, December 11, 2010 at 8:11pm
Torque=momentinertia*anglular acceleration

Torque= I * angacc

but

wf^2=wi^2+2*angacc*displacement

wf^2=wi^2+2*angacc*revolutions*2PI

where w is in rad/sec, angacc in rad/sec^2

solve for angacc, then torque

## Answer this Question

## Related Questions

- physics - A 4.0 kg pulley of radius 0.15 m is pivoted about an axis through its ...
- physics - A pulley rotating in the counterclockwise direction is attached to a ...
- Physics, please help me today. - four pulleys are connected by two belts. Pulley...
- Physics - A spinning disk of mass 5.0 kg and radius 0.25m is rotating about an ...
- physics - A spinning disk of mass 5.0 kg and radius 0.25m is rotating about an ...
- dynamics - 13. The constant angular acceleration of a pulley is 4 rad/s2 and its...
- math - the constant angular acceleration of pulley is 4rad/s2, angular speed 3 ...
- physics - A disk rotates about its central axis starting from rest and ...
- Physics - A hollow sphere of radius 25 cm is rotating at 13 rad/ sec about an ...
- physics - Two children, each with mass m = 11.0 kg, sit on opposite ends of a ...

More Related Questions