Before a collision, a 28 kg object is moving at +13 m/s. Find the impulse

Hmmmmm. Impulse is equal to change in momentum. There is no change mentioned here

I think the answer is this:

The change of momentum of a system is equal to the net impulse applied to it. Therefore,

delta p=Fnet*deltat=Impulse

In our case, p initial=mv=28kg*13m/s=364 kg*m/s
p final=0 ( the object stops, v=o, p final 0)

delta p = p final- p initial = 0- 364 = -364 kg*m/s

Hope, that's the right answer.

To find the impulse, you need to know the mass of the object and the change in its velocity caused by the collision. In this case, the mass (m) of the object is 28 kg, and the change in velocity (Δv) is the final velocity (vf) minus the initial velocity (vi).

Given:
Mass (m) = 28 kg
Initial velocity (vi) = +13 m/s

We don't have the final velocity (vf), so we need more information to calculate the change in velocity. If you have the final velocity after the collision, you can simply subtract the initial velocity to find Δv.

Once you have the change in velocity, you can calculate impulse (J) using the formula:

Impulse (J) = mass (m) × change in velocity (Δv)

Please provide more information on the final velocity or any other relevant details, and I'll be happy to help you calculate the impulse.