Posted by **devin** on Saturday, December 11, 2010 at 4:43pm.

A 70 kg painter is painting the wall of a building. He stands on a horizontal board of length 4.7 m and mass 15 kg, suspended from vertical ropes attached to each end. If the painter stands 2.0 m from one end of the board, what would the tensions in the ropes be?

Near rope:

Far rope:

- physics -
**drwls**, Saturday, December 11, 2010 at 5:33pm
T1 + T2 = (70 + 15)*g is one equation you need.

For the other equation, set the moment about either end equal to zero. If the painter stands 2 m from end 1,

T2*4.7 - M(board)*g*2.35 - M(painter)*g*2 = 0

Solve for T2. Then use the f1rst equation for T1.

## Answer this Question

## Related Questions

- Physics - A 3.0m wooden platform is suspended from the roof of a house by ropes ...
- physics - A 4-m wooden platform weighing 160 N is suspended from the roof of a ...
- Physics - A scaffold of mass 60 kg and length 5.0 m is supported in a horizontal...
- physics - A scaffold (a uniform horizontal board of mass 50 kg and length 4 m) ...
- phy - A scaffold of mass 50 kg and length 7.0 m is supported in a horizontal ...
- Physics - A uniform rigid pole of length L and mass M is to be supported from a ...
- physics - A uniform rigid pole of length L and mass M is to be supported from a ...
- physics - A uniform rigid pole of length L and mass M is to be supported from a ...
- physics - A uniform rigid pole of length L and mass M is to be supported from a ...
- physics! center of mass - a long non uniform board of length 8 m and mass m = 12...

More Related Questions