Posted by **Anonymous** on Saturday, December 11, 2010 at 4:05pm.

a boat starts at point A, moves 3km due north, then 2 km due east, then 1 km due south, and then 4 km due east to point b. Find the distance AB

- Math -
**MathMate**, Saturday, December 11, 2010 at 6:05pm
Add up each component (north or east) separately, and finally find the distance by the vectorial sum (using Pythagoras).

North: 3-1=2km

East: 2+4=6

Distance = √(2²+6²)

=√(40)

=2√(10)

- Math -
**Triquenita**, Saturday, December 11, 2010 at 7:41pm
I don't understand where for North you put 3-1. The boat moved 1km South and 3km North. Is that how this was done?

- Math -
**MathMate**, Saturday, December 11, 2010 at 9:05pm
In vectors, directions are *signed*.

This means that if we take the positive direction as north, then going south is backwards, and is thus represented as negative. Otherwise it would not make a difference between going 3 km north and 1 km north (3+1), and going 3 km north and 1 km south (3-1).

Hope that clarifies how it's done.

- Math -
**efrata**, Thursday, October 2, 2014 at 2:08pm
similar to other

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