Posted by **Kelly** on Saturday, December 11, 2010 at 3:38pm.

An object initially at rest experiences an acceleration of 1.4 m/s^2 for 5.0s and then travels at that constant velocity for another 7.0s. What is the object's average velocity over the 12s interval?

- College Physics -
**MathMate**, Saturday, December 11, 2010 at 6:14pm
Draw the time-velocity graph.

Initial velocity, u = 0

Acceleration, a = 1.4 m/s²

time, t = 5 seconds

Distance, S1 = ut+(1/2)at²

= 0*5 + (1/2)1.4*5²

= 17.5 m

Final velocity, v = u+at = 0+1.4*5 = 7 m/s

Distance, S2 = 7*7 = 49 m

Average velocity = (S1+S2)/(t1+t2)

=(17.5+49)/(5+7)

= 66.5/12

= 5.54 m/s

## Answer this Question

## Related Questions

- Physics - An object initially at rest experiences an acceleration of 1.4m/s2 for...
- Physics - An object is observed for a 5 second interval. During this time, the ...
- physics - In this problem you will determine the average velocity of a moving ...
- College Physics - An object moves with constant acceleration 4.95 m/s2 and over ...
- Physics - An object at rest accelerates through a distance of 1.5 m at which ...
- Physics - An object at rest accelerates through a distance of 1.5 m at which ...
- physics - Three forces acting on an object are given by F1 = ( - 1.85i + 2.50j) ...
- Physics - **I JUST NEED THE STEPS ON HOW TO SOLVE THE PROBLEMS** An object ...
- physics - An object moves with constant acceleration 3.65 m/s2 and over a time ...
- Physics - An object experiences a constant acceleration of 4.0 m/s2 along the &#...

More Related Questions