Posted by **Kelly** on Saturday, December 11, 2010 at 3:38pm.

An object initially at rest experiences an acceleration of 1.4 m/s^2 for 5.0s and then travels at that constant velocity for another 7.0s. What is the object's average velocity over the 12s interval?

- College Physics -
**MathMate**, Saturday, December 11, 2010 at 6:14pm
Draw the time-velocity graph.

Initial velocity, u = 0

Acceleration, a = 1.4 m/s²

time, t = 5 seconds

Distance, S1 = ut+(1/2)at²

= 0*5 + (1/2)1.4*5²

= 17.5 m

Final velocity, v = u+at = 0+1.4*5 = 7 m/s

Distance, S2 = 7*7 = 49 m

Average velocity = (S1+S2)/(t1+t2)

=(17.5+49)/(5+7)

= 66.5/12

= 5.54 m/s

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