What is the molarity of the resultant MgCl2 solution formed by mixing 100 cm3 of 0.5 M MgCl2 solution and 150 cm3 of 0.9M MgCl2 solution?
moles soln 1 = M x L = ??
moles soln 2 = M x L = ??
M mixed(resultant) soln = total moles/total L.
To find the molarity of the resultant MgCl2 solution, we need to use the formula:
M1V1 + M2V2 = M3V3
where:
M1 is the molarity of the first solution (0.5 M)
V1 is the volume of the first solution (100 cm3)
M2 is the molarity of the second solution (0.9 M)
V2 is the volume of the second solution (150 cm3)
M3 is the molarity of the resultant solution (unknown)
V3 is the total volume of the resultant solution (V1 + V2 = 100 cm3 + 150 cm3 = 250 cm3)
Let's substitute the values into the formula:
(0.5 M)(100 cm3) + (0.9 M)(150 cm3) = M3(250 cm3)
50 + 135 = M3(250)
185 = 250M3
Now, let's solve for M3:
M3 = 185/250
M3 = 0.74 M
Therefore, the molarity of the resultant MgCl2 solution formed by mixing the two solutions is 0.74 M.
To find the molarity of the resultant MgCl2 solution, we need to calculate the total moles of MgCl2 in the mixture and then divide it by the total volume of the mixture.
First, let's find the moles of MgCl2 in each solution. The formula to calculate moles is Moles = Molarity * Volume (in liters).
For the 100 cm3 of 0.5 M MgCl2 solution:
Volume = 100 cm3 = 100/1000 = 0.1 liters
Moles = 0.5 M * 0.1 L = 0.05 moles
For the 150 cm3 of 0.9 M MgCl2 solution:
Volume = 150 cm3 = 150/1000 = 0.15 liters
Moles = 0.9 M * 0.15 L = 0.135 moles
Now, we can find the total moles of MgCl2 by adding the moles from both solutions:
Total moles = 0.05 moles + 0.135 moles = 0.185 moles
Next, we need to determine the total volume of the mixture. Since we have 100 cm3 and 150 cm3, the total volume would be 100 cm3 + 150 cm3 = 250 cm3. However, we need the volume in liters, so we divide by 1000 to convert:
Total volume = 250 cm3 = 250/1000 = 0.25 liters
Finally, we can calculate the molarity using the formula Molarity = Moles/Volume:
Molarity = 0.185 moles / 0.25 L = 0.74 M
Therefore, the molarity of the resultant MgCl2 solution formed by mixing the two solutions is 0.74 M.