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July 30, 2014

July 30, 2014

Posted by **Terri** on Saturday, December 11, 2010 at 9:51am.

f(x)=-2x^(2)÷-x^(2)-6x-27

- Pre-Cal -
**Reiny**, Saturday, December 11, 2010 at 10:30amI will assume you meant

f(x) = -2x^2 /(-x^2 - 6x - 27)

= 2x^2/(x^2 + 6x + 27)

Are you sure you typed the signs correctly?

It would be nice if the -27 had been +27, or the - in front of x^2 would not be there.

If it is correct,

since x^2 + 6x + 27 = 0 has no real roots, the domain would be the set of all real numbers.

if you meant:

f(x)= (-2x^(2)÷-x^(2))-6x-27 , then the domain is the set of real numbers except x ≠ 0

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