Posted by **vanessa** on Saturday, December 11, 2010 at 12:57am.

a particle moving at a velocity of 6 m/s in the positive x direction is given an acceleration of 3.9m/s^2 in the positive Y direction for 3.4s. what is the final speed of the particle? answer in units of m/s

- physics -
**drwls**, Saturday, December 11, 2010 at 3:16am
The x component of velocity remains

Vx = 6 m/s.

The y component of velocity increases with time, t, and is

Vy = 3.9 t. After 3.4 seconds

Vy(@ t=3.4s) = 13.3 m/s

The final speed (the magnitude of velocity) is sqrt(Vx^2 + Vy^2)

which is about 14.6 m/s

- physcis -
**Anonymous**, Thursday, October 29, 2015 at 11:01pm
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- physcis -
**gago**, Saturday, January 30, 2016 at 3:02pm
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