Posted by pete on Friday, December 10, 2010 at 4:37pm.
Is this horizontal distance? If so, draw the triangle. 1.5 down, .24 left, and hypotenuse is sqrt (1.5^2+.24^2)
but the pendulum is not that long, it is 1.5, so at what height is the bob at?
similar triangles: h/1.5=(sqrt(1.5^2+.24^2) -1.5)/1.5
solve for h.
then mgh=1/2 m v^2 solve for v.
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