How much heat must be added to 0.55 kg of aluminum to change it from a solid at 180°C to a liquid at 660°C (its melting point)? The latent heat of fusion for aluminum is 4.0 105 J/kg.

Q=mc∆t

http://www.ausetute.com.au/heatcapa.html

would it be .55 converted to g times cg of aluminum which according to the link is .90 time the differnece in T which is 660-180

im wondering the same thing as leah cause i left mass in kg and it was marked wrong please help

To determine how much heat must be added to change aluminum from a solid to a liquid, we need to consider two parts: the heat needed to raise the temperature from 180°C to the melting point (660°C) and the heat needed for the phase change from solid to liquid.

Step 1: Calculate the heat needed to raise the temperature:
The specific heat capacity (c) of aluminum is 0.9 J/g°C or 900 J/kg°C.

First, let's convert the mass of aluminum from kg to grams:
0.55 kg = 550 grams.

Next, calculate the heat required to raise the temperature from 180°C to the melting point:
Heat = mass x specific heat capacity x change in temperature
Heat = 550 g x 900 J/kg°C x (660°C - 180°C)

Step 2: Calculate the heat needed for the phase change:
The latent heat of fusion (L) for aluminum is 4.0 × 10^5 J/kg.

The mass of aluminum is still 550 grams.

Heat = mass x latent heat of fusion
Heat = 550 g x 4.0 × 10^5 J/kg

Step 3: Add the two heats together to find the total heat required:
Total heat = heat required to raise the temperature + heat required for the phase change

Now, add the two heats calculated in step 1 and step 2:
Total heat = (550 g x 900 J/kg°C x (660°C - 180°C)) + (550 g x 4.0 × 10^5 J/kg)

Calculating this expression will give you the final answer for how much heat must be added to change the aluminum from a solid at 180°C to a liquid at 660°C.