a man exerts 200 N force on a 18 kg lawnmower handle as he pushes it at constant velocity . the hantle makes an angle os 50 degrees with the ground.
What is your question? The coefficient of friction while mowing grass?
To find the acceleration of the lawnmower, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force acting on the lawnmower is the force exerted by the man, minus the force of friction:
Net Force = Force applied - Force of friction
Since the lawnmower is moving at a constant velocity, the acceleration is zero. This means the net force is also zero because there is no acceleration.
Therefore, the force applied by the man is equal to the force of friction:
Force applied = Force of friction
The force of friction can be calculated using the equation:
Force of friction = coefficient of friction * normal force
The normal force is the force exerted by a surface to support the weight of an object resting on it. It is equal to the weight of the lawnmower in this case.
The weight of the lawnmower can be calculated using the equation:
Weight = mass * acceleration due to gravity
Now, let's break down the given information:
Force applied by the man = 200 N
Mass of the lawnmower = 18 kg
Angle between the lawnmower handle and the ground = 50 degrees
First, we need to calculate the weight of the lawnmower:
Weight = mass * acceleration due to gravity
Weight = 18 kg * 9.8 m/s^2
Weight ≈ 176.4 N
Next, we need to calculate the normal force (which is equal to the weight):
Normal force = 176.4 N
Finally, we can calculate the force of friction:
Force of friction = coefficient of friction * normal force
However, since we don't have the coefficient of friction, we cannot calculate the force of friction accurately.