posted by Bobby on .
Consider the motion of a projectile. It isfired at t = 0. Its initial speed is 36 m/s and its initial projection angle is 55◦ from the horizontal.
The acceleration of gravity is 9.8 m/s2 . y
What is the maximum height, h, of its tra jectory?
Answer in units of m.
Maximum height is achieved when the velocity's vertical component is zero.
36*sin55 - gt = 0
Solve for the time t. Then use
y = 30*sin55* t - (g/2)t^2
to get the maximum altitude h.