A worker pushes a 820 N crate with a horizontal force of 345 N a distance of 24 m. Assume the coefficient of kinetic frictin between the crate and the floor is 0.22.
a) How much work is done by the worker on the crate?
b) How much work is done by the floor?
c) What is the net work done on the crate?
physics. please help - drwls, Thursday, December 9, 2010 at 10:05pm
a) 345 N*24 m = ___ J
b) -820 N*(0.22)*24 m = - ___ J
c) Add the previous two results.
(Note that (b) is negative)