Posted by Brian on Thursday, December 9, 2010 at 8:29pm.
net work= friction work+ changein PE
net work= .350*distance+mg*distance
0.1
when they fall the ball
(0.075)(9.81)(1.32)= 0.971 J
then, (0.350)(1.32)= 0.462J
then, 0.971- 0.462= 0.509J ~ work done on the ball
F=mg, so force = mass times gravity.
0.075 times 9.8 = 0.735
W=FD, so work= force times displacement.
0.735 times 1.32= 0.9702 J.
So, 0.9702 is the first amount of work.
Second, frictional force times displacement.
0.350 times 1.32 = 0.462 J.
Subtract them to get the net force, so:
0.9702 - 0.462 = 0.51 J
0.51 J is therefore the answer.
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