how many grams of water do you have if it takes 3000j to raise the temperature from 21c to 100c
To determine the number of grams of water, we need to use the formula:
q = m * c * ΔT
where:
q is the amount of heat energy (in Joules),
m is the mass of the water (in grams),
c is the specific heat capacity of water (which is approximately 4.18 J/g°C),
ΔT is the change in temperature (in °C).
We are given that the heat energy (q) required to raise the temperature of water from 21°C to 100°C is 3000 J.
Let's plug in the values and solve for the mass (m):
3000 J = m * 4.18 J/g°C * (100°C - 21°C)
Simplifying the equation:
3000 J = m * 4.18 J/g°C * 79°C
Divide both sides of the equation by (4.18 J/g°C * 79°C):
3000 J / (4.18 J/g°C * 79°C) = m
Calculating the result:
m ≈ 9.017 grams
Therefore, you have approximately 9.017 grams of water.