Posted by john on Thursday, December 9, 2010 at 6:14pm.
The area of a regular hexagon of side 4m is the same as that of 6 equilateral triangles with side 4m.
Area of an equilateral triangle
A=s²*√(3)/4
=4²*√(3)/4
=4√(3)
For the regular hexagon,
6A=24√(3)
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