Posted by Angel on .
Consider the resonant frequencies of a 1.78 m tube closed at one end at 24°C.
a) Lowest resonant frequency = Hz
HELP: You know the length of the tube. What else do you need in order to calculate the frequency of the lowest resonance of a tube that's closed at one end?
HELP: How does the speed of sound in air depend on the temperature?
b) Frequency differences between successive higher resonances = Hz
HELP: You can calculate the frequencies of successive resonances. They are always the same distance apart, in Hz.
c) Number of higher resonances audible to the humans = (enter an integer)
HELP: 20 kHz is the highest frequency audible to the "normal" ear.
HELP: How many of the differences you calculated in part b) will fit between the lowest resonance and the highest normally audible frequency?
de rosunant in n3-m is 4