Posted by **joey** on Thursday, December 9, 2010 at 3:22pm.

A bullet of mass 8 g strikes a ballistic pendulum of mass 2.0 kg. The center of mass of the pendulum rises a vertical distance of 10 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

- physics -
**bobpursley**, Thursday, December 9, 2010 at 3:29pm
The momentum of the bullet: massbullet*velocity

that has to equal the momentum of the block and bullet combination at impact(mblock+massbullet)V set them equal, and solve for V.

Now, the initialKE of the block and bullet combination is 1/2 (totalmass)V^2

set that equal to the change in PEnergy

totalmass*g*height.

solve for height in terms of initial bullet velocity.

WEll, you know height, so you can solve for bullet velocity.

## Answer This Question

## Related Questions

- Physics - A bullet of mass 3.2 g strikes a ballistic pendulum of mass 3.6 kg. ...
- physics for physical science - a bullet of mass 0.015kg strikes ballistic ...
- Physics - A bullet of mass 4.8 g strikes a ballistic pendulum of mass 3.3 kg. ...
- physics - a bullet of mass 0.015kg strikes a ballistic pendullum of mass 2kg.the...
- physics - A ballistic pendulum consists of a rectangular wooden block of mass 1....
- physics - A(n) 3.46 g bullet is fired into a(n) 2.4 kg ballistic pendulum and ...
- Physics - A(n) 5.52 g bullet is fired into a(n) 3.07 kg ballistic pendulum and ...
- mambane - A 10.0g bullet is fired with a speed of 500m/s into a pendulum block ...
- Physics - A ballistic pendulum was a device used in the past century to measure ...
- physics - A ballistic pendulum, as shown in the figure, was a device used in the...

More Related Questions