How to find the molarity of NaOH when the given is 0.1803 grams of KHPg/mol molecular w. of KHP is 204.2 9.7 ml NaOH
KHP or potassium hydrogen phthalate is a monoprotic acid used as a primary standard.
so
KHP + NaOH -> KNaP + H2O
if 0.1803 g of KHP has been used, this is
0.1803 g/204.2 g mol^-1
=8.829 x 10^-1 mole
which reacts with the same number of moles of NaOH
so concentration of NaOH is
8.829 x 10^-1 mole /0.0097 L
=0.091 M
only 2 sig figs justified here as only 2 sig figs in volume of NaOH, even though mass and molar mass of KHP are given to 4 sig figs.
Check my maths.