Posted by Amy on Thursday, December 9, 2010 at 12:31am.
What you want in the probability of selecting 1, 2 or 3 defective pens.
P of 3 = 4/15 * 3/14 * 2/13
P of 2 = 4/15 * 3/14 * 11/13
P of 1 = 4/15 * 11/14 * 10/13
The answer is the sum of those three products.
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