Posted by **Lee** on Wednesday, December 8, 2010 at 10:05pm.

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. If the area of printed material on the poster is fixed at 1536 cm^2, find the dimensions of the poster with the smallest area.

- Cal 1 -
**MathMate**, Wednesday, December 8, 2010 at 11:24pm
Let the width of the image (excluding margins) be x, then the height is 1536-x.

The total area of the poster,

A(x)=(x+2*8)(1536/x+2*12)

Differentiate with respect to x, equate to zero and solve for x. I get x=32.

- Cal 1 -
**MathMate**, Thursday, December 9, 2010 at 8:00pm
Is there anything that you don't follow?

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