Sunday

December 21, 2014

December 21, 2014

Posted by **Moi** on Wednesday, December 8, 2010 at 8:42pm.

Thanks

- Logarithm law question -
**MathMate**, Wednesday, December 8, 2010 at 9:20pme^(2t) is equal to e^(t^2)

*if and only if*t=2 or t=0, simply because 2t=t² for these two values of t.

Since in general, 2t≠t², e^(2t) is*not*equivalent to e^(t^2).

For example, t=4,

e^{2t}=e^{8}=2980.96

e^{t²}=e^{16}=8886110.52

The confusion arises probably because

e^{2t}=(e^{t})²

while

e^{t²}=(e^t)^t

Hope that clears it up.

**Answer this Question**

**Related Questions**

Math - Hello I was wondering if you can help me with a question, I cant seem to ...

Physics hw question mistake - Hello, I didn't post the correct questions ...

Math - Choose True or False for each of the following. 87% is equivalent to 0.87...

anatomy - I can't seem to find the answer to this question anywhere, thanks. ...

12 Chemistry - What is the molar enthalpy of combustion of magnesium? This was ...

business law - Libertarians are also referred to as economic socialists. True Is...

business law - Libertarians are also referred to as economic socialists. True Is...

Math - Evaluate log(6)√6 (actual question) There's a problem in my book ...

math - use a commutative law to find an equivalent expression pq. an equivalent ...

Canadian Law - I was asked the question, what are some principles of law that ...