Wednesday

September 17, 2014

September 17, 2014

Posted by **Megan** on Wednesday, December 8, 2010 at 8:20pm.

- Precalculus -
**MathMate**, Wednesday, December 8, 2010 at 9:32pmUse the identity sin²(x)=1-cos²(x).

So

2sin^2x+3cosx=3 becomes

2cos²(x)-3cos(x)-1=0

Solve the quadratic for cos(x),

I get cos(x)=1 or cos(x)=1/2

On the interval [0,2π], each value of cos(x) has two solutions for a total of 4 values of x.

**Answer this Question**

**Related Questions**

Math - Can I please get some help on these questions: 1. How many solutions does...

trig - Find all solutions of the equation 2sin^2x-cosx=1 in the interval [0,2pi...

trig - I need to find all solutions of the given equations for the indicated ...

Math Trig - Find all solutions on the interval [0,2pi] for the following: 2sin^2...

Precalculus - 2sin^2x+3cosx=3

Trig - Find all of the solutions between 0 and 2pi: 2sin(x)^2 = 2 + cos(x)

Precalculus II - Find exactly all solutions in [0,2pi) to 4sin(x)cos(x) = 1

pre calc - find all solutions on 0 is greater than or equal to theta < 2pi ...

math - find all solutions on 0 is greater than or equal to theta < 2pi cos ...

trig - Find ALL solutions to the equation on the interval [0, 2pie]: 2sin(1/2X...