The specific heat capacity of Lead is 0.127J/degrees C*g. What is the molar heat capacity of Lead? What is the heat capacity of a lead cylinder that has a mass of 235000g?

0.127 J/g*C x (molar mass Pb/1 mole Pb) = ??

0.127 J/g*C x 235000 grams = ?? J/C

26.49

To find the molar heat capacity of lead, we need to know the molar mass of lead.

The molar mass of lead (Pb) is approximately 207.2 g/mol.

To calculate the molar heat capacity, we can use the equation:

Molar Heat Capacity = Specific Heat Capacity / Molar Mass

Molar Heat Capacity of Lead = 0.127 J/°C*g / 207.2 g/mol

Molar Heat Capacity of Lead = 0.000613 J/°C/mol

Now, let's calculate the heat capacity of the lead cylinder that has a mass of 235000 g.

Heat Capacity = Specific Heat Capacity * Mass

Heat Capacity = 0.127 J/°C*g * 235000 g

Heat Capacity = 29845 J/°C

Therefore, the molar heat capacity of lead is 0.000613 J/°C/mol, and the heat capacity of the lead cylinder with a mass of 235000 g is 29845 J/°C.

To find the molar heat capacity of lead, we need to know its molar mass (denoted by M) and the specific heat capacity.

1. First, we need to determine the molar mass of lead. The atomic mass of lead (Pb) is approximately 207.2 g/mol. Therefore, the molar mass of lead is 207.2 g/mol.

2. To find the molar heat capacity, we can use the formula:
Molar heat capacity (Cp) = Specific heat capacity (C) * Molar mass (M)

Substituting the values we have:
Cp = 0.127 J/°C*g * 207.2 g/mol
Cp = 26.344 J/°C*mol (moles cancel out with grams)

Therefore, the molar heat capacity of lead is approximately 26.344 J/°C*mol.

To find the heat capacity of a lead cylinder with a mass of 235000 g, we need to apply the equation:

3. Heat capacity is calculated using the equation:
Heat capacity (C) = Specific heat capacity (c) * Mass (m)

Substituting the given values:
C = 0.127 J/°C*g * 235000 g
C = 29,845 J/°C

Therefore, the heat capacity of the lead cylinder with a mass of 235000 g is approximately 29,845 J/°C.