The moment of inertia about the pole(origin) of the plane region which is inside the cardiod: r = 1 + cosO and outside the circle r =1. It's mass density is equal to it's distance from the pole..... I need someone who is way smarter than me to help with this one... please and thank you.

Sure! I'll be happy to assist you. Let's break down the problem step by step.

To find the moment of inertia about the pole, we need to integrate the mass elements within the plane region.

First, let's try to understand the two equations describing the shape.

1. r = 1 + cosθ represents a cardioid curve, where θ represents the angle measured from the positive x-axis.

2. r = 1 represents a circle with radius 1 centered at the pole (origin).

The problem states that the mass density is equal to the distance from the pole. This means that the mass per unit area at any point in the plane is equal to the radial distance from the pole.

To calculate the moment of inertia, we will use the formula for a continuous body:

I = ∫ r^2 dm

Now, let's derive the equation for the mass element dm. We know that the mass per unit area is equal to the distance from the pole (r). Therefore, the mass in a small area element dA is given by:

dm = ρ dA

where ρ represents the mass density. Since we know the mass density is equal to the distance from the pole (r), we have:

dm = r dA

To integrate this equation, we need to express dA in terms of θ.

The area element dA can be expressed as:

dA = r dr dθ

Since we want the area element dA in terms of θ, we need to express the radius (r) in terms of θ.

From the given equations, we have:

r = 1 + cosθ for the cardioid (inside)

r = 1 for the circle (outside)

So, in the region inside the cardioid, we can write:

dA = (1 + cosθ) dr dθ

Now, we have all the components to calculate the moment of inertia. We substitute dm and dA back into the integral:

I = ∫ r^2 dm
= ∫ (r^2)(r dA)
= ∫ (r^3)(1 + cosθ) dr dθ

To solve this integral, you would need to evaluate it over the appropriate limits of integration. The limits of integration will depend on the desired region within the plane.

I hope this explanation helps! If you have any further questions or if there's anything else I can assist you with, please let me know.