How many moles of carbon monoxide gas are produced when 2.88 moles of SnO2(s) react with excess carbon according to the equation below?
SnO2(s) + 2C(s) --> Sn(s) + 2CO(g)
How do you figure all of this out?
To figure out the number of moles of carbon monoxide gas produced in the reaction, you need to use stoichiometry.
1. Start by identifying the given information from the question.
- The question states that 2.88 moles of SnO2(s) react.
- The balanced chemical equation shows the stoichiometric ratio between SnO2 and CO as 1:2.
2. Use the stoichiometric ratio from the balanced equation to calculate the number of moles of CO produced.
- Since the stoichiometric ratio is 1:2 for SnO2 and CO, this means that for every 1 mole of SnO2, 2 moles of CO are produced.
- Multiply the number of moles of SnO2 by the stoichiometric ratio.
(2.88 mol SnO2) x (2 mol CO / 1 mol SnO2) = 5.76 mol CO
Therefore, 5.76 moles of carbon monoxide gas are produced when 2.88 moles of SnO2 react with excess carbon according to the given equation.
Here is a worked example of stoichiometry. Jsut follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html