Posted by Stacy on Wednesday, December 8, 2010 at 6:12pm.
Convert 4.23 g MgBr2 to moles and multiply that by 2 to obtain moles Br^- from MgBr2. moles = grams/molar mass.
Convert 1.21 g KBr the same way. Add the moles Br^- together to obtain total moles, then remember that 1 mole of Br^- ions will contain 6.022E23 ions.
4.23g MgBr2 Moles= grams/molar mass
4.23/184.113 = 0.023 moles
1.21g KBr Moles= grams/molar mass
1.21/119.002 = 0.033
and than what? I add those two #'s together? 0.033 + 0.023 = 0.033
and I dont know what you mean by 1 mole of Br- ions will contain 6.022e23 ions where did you get that info?
Thanks!
Related Questions
chemistry - Determine the number of bromide ions in solution when 4.23 g of ...
chemistry - If 50.0 mL of 0.150 M magnesium bromide is combined with 200 mL of 0...
Chemistry - A 3.214-g sample of magnesium reacts with 8.416g of bromine. The ...
Chemistry - Need Help On This Question.! Potassium chloride reacts with bromine ...
CHEMISTRY - Consider an aqueous solution prepared from 250.0 mL of water and 1....
CHEM - how many gram of potassium bromide can be made from 13.7 grams of ...
chemistry - I need to balance hydrolysis equations for the following salts,...
Organic Chemistry - What is the structure of the magnesium salt that is created ...
Chemistry - a student was asked to determine the&...
chemistry - when chlorine gas is bubbled into a solution of sodium bromide, the ...
For Further Reading
