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A violin has an open string length (bridge to nut) of L=32.7 cm. At what distance x from the bridge does a violinist have to place his finger on the fingerboard to play a C (523.3 Hz) on the A string (fundamental frequency 440 Hz)?

  • Physics -

    fundamental frequency (ff) = 440 Hz
    frequency at C (fc)= 523.3 Hz
    L = 32.7 cm
    L(C) = ?
    x(C) = ?

    L (C) = L * ff/fc
    L (C) = 27.50 cm

    x (C) = L - L(C) = 5.20 cm

    Finger has to be placed at 5.20 cm from the end.

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