one number is 6 more than another. their product is 91. what is the number?

x is 6 more than z ther product is the number?

i just re-wrote it with letters... witch letter is it that needs to be solved?

what number*

sorry. i don't really know

13 & 7

To find the two numbers, let's call them x and y.

According to the problem, one number is 6 more than the other. We can represent this relationship with the equation: x = y + 6.

The problem also states that the product of the two numbers is 91. This can be represented by another equation: x * y = 91.

Now we have a system of two equations with two variables:
1) x = y + 6
2) x * y = 91

To solve this system of equations, we can use the substitution method.

From equation 1), substitute the value of x from equation 2): (y + 6) * y = 91

Expanding the equation: y^2 + 6y = 91

Rearranging the equation: y^2 + 6y - 91 = 0

Now, we can solve this quadratic equation using factoring, completing the square, or the quadratic formula.

Factoring: (y - 7)(y + 13) = 0

So, y - 7 = 0 or y + 13 = 0

Solving for y, we have two possible solutions: y = 7 or y = -13.

Now let's substitute these values back into equation 1) to find x:

For y = 7: x = 7 + 6 = 13

For y = -13: x = -13 + 6 = -7

Therefore, the two numbers are 13 and 7 or -7 and -13.