Posted by **Lisa, Help needed!** on Wednesday, December 8, 2010 at 5:14pm.

To what volume should you dilute 131 mL of an 8.20 M CuCl2 solution so that 49.0 mL of the diluted solution contains 4.53g CuCl2 ?

Chemistry...Help!! - Dr Russ, Wednesday, December 8, 2010 at 4:43am

Molar mass of CuCl2 is 134.5 g mol^-1

so solution needs to contain

4.53 g / 134.5 g mol^-1

=0.03368 mole

concentration is

0.049 L/0.03368 mole

=1.455 molar

thus we need to dilute the 8.20 M solution by a factor

8.20 M/1.455 M= 5.636

so the new total volume is

131 ml x 5.636

=738.4 ml

check on the concentration

old solution contains

131 x 8.20 mmoles = 1074 mmoles

new solution contains

1.455 x 738.4 mmole = 1074 mmole

Chemistry...Help!! - Lisa, Help needed!, Wednesday, December 8, 2010 at 1:59pm

Thank you for all the detail, but i'm still confused......so 738.4mL is the answer?

- chemistry -
**DrBob222**, Wednesday, December 8, 2010 at 5:26pm
It doesn't help us help you if you simply say you are confused without telling us what you understand, what you don't understand, and if possible, why you don't understand.

- chemistry -
**Anonymous**, Tuesday, February 1, 2011 at 6:01pm
the second part is moles/volume not volume/moles

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