C4 H10 O2

ppm = 3.25 singlet 6H

ppm = 3.45 singlet 4H

C4 H10 O2

ppm = 3.25 singlet 6H

ppm = 3.45 singlet 4H

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what is the structure of the compound that is an obvious question for NMR

The given information is a chemical formula "C4H10O2" and two sets of data regarding proton (H) NMR spectroscopy: "ppm = 3.25 singlet 6H" and "ppm = 3.45 singlet 4H." We need to figure out the structure of the molecule based on this information.

To determine the structure, we can start by analyzing the molecular formula "C4H10O2." This formula indicates that the molecule contains 4 carbon (C) atoms, 10 hydrogen (H) atoms, and 2 oxygen (O) atoms.

Next, let's analyze the given NMR data. The ppm value represents the chemical shift, which provides information about the electronic environment around the hydrogen atoms. The singlet indicates that the proton signals occur as a single peak, implying that the hydrogens are equivalent and not split by neighboring protons.

According to the first set of data, "ppm = 3.25 singlet 6H," we have six hydrogens (6H) resonating at 3.25 ppm. Since they are equivalent and show a singlet signal, they must be attached to the same type of carbon atom (C). Therefore, we have a cluster of six hydrogens bonded to the same type of carbon.

Moving on to the second set of data, "ppm = 3.45 singlet 4H," we have four hydrogens (4H) resonating at 3.45 ppm. Like the previous case, they are equivalent and display a singlet signal. Hence, we have another group of four hydrogens attached to the same type of carbon atom.

Based on the given information, we can conclude that the molecule has two different types of carbon atoms. One type of carbon atom is attached to six hydrogens, while the other type is linked to four hydrogens.

To deduce the overall structure, we need additional information about the connectivity of these carbon atoms and the oxygen atoms.