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March 1, 2015

March 1, 2015

Posted by **Edith** on Wednesday, December 8, 2010 at 3:30pm.

- physics -
**MathMate**, Wednesday, December 8, 2010 at 6:08pmThe magnitude of AxB is C=|A||B|sinθ

while the magnitude of A.B is

D=|A||B|cosθ

So if

D/C=3 => cotθ=3

Solve for θ

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