Write the 12 mole ratios that can be derived from the equation for the combustion of isopropyl alcohol?
To determine the mole ratios in the combustion of isopropyl alcohol, we first need to write the balanced equation for the combustion reaction. The chemical formula of isopropyl alcohol is C3H8O.
The balanced equation for the combustion of isopropyl alcohol is:
C3H8O + 5O2 → 3CO2 + 4H2O
Now, we can derive the mole ratios by comparing the coefficients of the elements or compounds involved in the reaction. The mole ratios can be obtained by dividing the coefficient of one substance by the coefficient of another substance.
Let's start with the mole ratios involving isopropyl alcohol (C3H8O):
1. Moles of C3H8O to Moles of CO2: 1:3 (coefficient ratio)
Next, let's consider the mole ratios involving oxygen (O2):
2. Moles of O2 to Moles of CO2: 5:3
3. Moles of O2 to Moles of H2O: 5:4
Now, let's move on to the mole ratios involving carbon dioxide (CO2):
4. Moles of CO2 to Moles of C3H8O: 3:1
5. Moles of CO2 to Moles of O2: 3:5
6. Moles of CO2 to Moles of H2O: 3:4
Next, let's look at the mole ratios involving water (H2O):
7. Moles of H2O to Moles of C3H8O: 4:1
8. Moles of H2O to Moles of O2: 4:5
9. Moles of H2O to Moles of CO2: 4:3
Lastly, let's consider the mole ratios involving carbon (C):
10. Moles of C to Moles of C3H8O: 3:1
11. Moles of C to Moles of CO2: 3:3 (same coefficient)
And the mole ratios involving hydrogen (H):
12. Moles of H to Moles of H2O: 8:4 (simplify to 2:1)
Remember, these mole ratios represent the stoichiometry of the reaction and can be used to calculate the amounts of substances involved in the combustion of isopropyl alcohol.