Please tell me if these are right!
What are the [H3O+] and [OH-] for a solution with the following pH values?
a. 10.0 I got 1.0*10^-10 for [H3O+] and 1.0*10^-4 for [OH-]
b. 5.0 I got 1.0*10^-5 for [H3O+] and 1.0*10^-9 for [OH-]
c. 7.00 I got 1.0*10^-7 for [H3O+] and1.0*10^-7 for [OH-]
d. 6.5 I got 3.2*10^-7 for [H3O+] and 3.125*10^-8 for [OH-]
e. 1.82 I got 1.5*10^-2 for [H3O+] and 6.7*10^-12 for [OH-]
Solution X has a pH of 9.5 and solution Y has a pH of 7.5.
b. what is the [H3O+] in each?
I got 3.2*10^-10 for [H3O+] and 3.125*10^-5 for [OH-] for 9.5
c. what is the [OH-] in each?
I got 3.2*10^-8 for [H3O+] and 3.125*10^-7 for [OH-] for 7.5.
Thank you so much!
It strikes me as odd that you round 3.162 to 3.2 but you carry 3.125 to many more places.I think you rounded too quickly (or too much) for d. If you had made that 3.16E-7 instead of 3.2, then the OH would have been 3.16E-8.
Second set.
b. same problem. 3.2 should be 3.16 and that changes the OH.
c. same problem. 3.2 should be 3.16 and that changes the OH.
To determine the [H3O+] and [OH-] for a solution with a given pH value, we can use the equation:
pH = -log[H3O+]
From this equation, we can calculate the [H3O+]:
[H3O+] = 10^(-pH)
Now let's go through each question and calculate the values mentioned.
a. pH = 10.0
[H3O+] = 10^(-10.0) = 1.0 × 10^(-10)
[OH-] can be calculated using the equation [OH-] = 1.0 × 10^(-14) / [H3O+].
[OH-] = 1.0 × 10^(-14)/1.0 × 10^(-10) = 1.0 × 10^(-4)
b. pH = 5.0
[H3O+] = 10^(-5.0) = 1.0 × 10^(-5)
[OH-] = 1.0 × 10^(-14)/1.0 × 10^(-5) = 1.0 × 10^(-9)
c. pH = 7.00
[H3O+] = 10^(-7.00) = 1.0 × 10^(-7)
[OH-] = 1.0 × 10^(-14)/1.0 × 10^(-7) = 1.0 × 10^(-7)
d. pH = 6.5
[H3O+] = 10^(-6.5) = 3.2 × 10^(-7)
[OH-] = 1.0 × 10^(-14)/3.2 × 10^(-7) = 3.125 × 10^(-8)
e. pH = 1.82
[H3O+] = 10^(-1.82) = 1.5 × 10^(-2)
[OH-] = 1.0 × 10^(-14)/1.5 × 10^(-2) = 6.7 × 10^(-12)
For the next set of questions:
Solution X has a pH of 9.5
[H3O+] = 10^(-9.5) = 3.2 × 10^(-10)
[OH-] = 1.0 × 10^(-14)/3.2 × 10^(-10) = 3.125 × 10^(-5)
Solution Y has a pH of 7.5
[H3O+] = 10^(-7.5) = 3.2 × 10^(-8)
[OH-] = 1.0 × 10^(-14)/3.2 × 10^(-8) = 3.125 × 10^(-7)
It seems like your calculations are correct for all the values mentioned. Well done! If you have any more questions or need further explanations, feel free to ask.